A note on maximal nonhamiltonian Burkard-Hammer graphs
Abstract
A graph G = (V, E) is called a split graph if there exists a partition V = I ∪K such that the subgraphs G[I] and G[K] of G induced by I and K are empty and complete graphs, respectively. In 1980, Burkard and Hammer gave a necessary condition for a split graph G with |I| < |K| to be hamiltonian. We will call a split graph G with |I| < |K| satisfying this condition a Burkard-Hammer graph. Further, a split graph G is called a maximal nonhamiltonian split graph if G is nonhamiltonian but G+uv is hamiltonian for every uv ∈ E where u ∈ I and v ∈ K. In an earlier work, the author and Iamjaroen have asked whether every maximal nonhamiltonian Burkard-Hammer graph G with the minimum degree δ(G) ≥ |I| − k where k ≥ 3 possesses a vertex adjacent to all vertices of G and whether every maximal nonhamiltonian Burkard-Hammer graph G with δ(G) = |I|−k where k > 3 and |I| > k +2 possesses a vertex with exactly k − 1 neighbors in I. The first question and the second one have been proved earlier to have a positive answer for k = 3 and k = 4, respectively. In this paper, we give a negative answer both to the first question for all k ≥ 4 and to the second question for all k ≥ 5.
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