1792 United States presidential election in New Hampshire

1792 United States presidential election in New Hampshire
← 1788–89 November 2 – December 5, 1792 1796 →
President before election; George Washington; Independent	Elected President ; George Washington; Independent

A presidential election was held in New Hampshire between November 2 to December 5, 1792, as part of the 1792 United States presidential election to elect the president. Voters chose five representatives, or electors, to the Electoral College, who voted for President and Vice President.

New Hampshire voted for incumbent George Washington without any competitor.

Results

1792 United States presidential election in New Hampshire^[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Independent	George Washington	2,762	100.00%	6
Totals			2,762	100.00%	6

1792 United States presidential election in New Hampshire^[2]
County	George Washington Federalist		Margin		Total votes^[a]
County	#	%	#	%	Total votes^[a]
Cheshire	52	100.00%	52	100.00%	52
Grafton	88	100.00%	88	100.00%	88
Hillsborough	50	100.00%	50	100.00%	50
Rockingham	202	100.00%	202	100.00%	202
Strafford	102	100.00%	102	100.00%	102
Total	494	100.00%	494	100.00%	494

^ Partial results are taken from the highest voted federalist, and anti-federalist elector for each county.^[2]

^ Dubin, Michael J. (2002). United States Presidential Elections, 1788-1860: The Official Results by County and State. Jefferson: McFarland & Company. ISBN 9780786410170.
^ ^a ^b "A New Nation Votes". elections.lib.tufts.edu. Retrieved January 15, 2026.

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