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of triangle ABC (see the diagram at right) and constructing the straight lines A'B, B'C and Slightly modified from Meyer, JH & Van Biljon, A, (2009), Proceedings of the 15" Annual AME: Congress, University of Free State, Bloemfontein, pp. 1-8.

Figure 2 of triangle ABC (see the diagram at right) and constructing the straight lines A'B, B'C and Slightly modified from Meyer, JH & Van Biljon, A, (2009), Proceedings of the 15" Annual AME: Congress, University of Free State, Bloemfontein, pp. 1-8.

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C'A to meet at D. Historical Notes
C'A to meet at D. Historical Notes
that will give us further insight leading to an interesting, and important generalization. concurrent at the centroid.” Let’s consider a non-traditional proof based on areas, but
that will give us further insight leading to an interesting, and important generalization. concurrent at the centroid.” Let’s consider a non-traditional proof based on areas, but
Figure 3: Proof of Fermat-Torricelli generalization
Figure 3: Proof of Fermat-Torricelli generalization
In order to prove this result we will use the following lemma, which is stated here without proof.
In order to prove this result we will use the following lemma, which is stated here without proof.
Using the aforementioned generalization of the Fermat-Torricelli point, it was now very
Using the aforementioned generalization of the Fermat-Torricelli point, it was now very
are concurrent. The proof follows similarly from the Fermat-Torricelli generalization. Concluding comment with the incentres of the triangles BCI,, CAI,, and ABI, (J; are the excentres of AABC)
are concurrent. The proof follows similarly from the Fermat-Torricelli generalization. Concluding comment with the incentres of the triangles BCI,, CAI,, and ABI, (J; are the excentres of AABC)
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Dynamic Geometry SofwareProof and Proving in Mathematics EducationGeometry
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