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Adding, this explains the result A; = 5Ao.  area(ABEF) = 2area(AABC); area(AHGD) = 2area(AADC); area(AHAE) = 2area(AABD); and area(AFCG) = 2area(ABCD).

Figure 7 Adding, this explains the result A; = 5Ao. area(ABEF) = 2area(AABC); area(AHGD) = 2area(AADC); area(AHAE) = 2area(AABD); and area(AFCG) = 2area(ABCD).