Triangles with Vertices Equidistant to a Pedal Triangle
2020, arXiv: Metric Geometry
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Abstract
In this paper, we present a synthetic solution to a geometric open problem involving the radical axis of two strangely defined circumcircles. The solution encapsulates two generalizations, one of which uses a powerful projective result relating isogonal conjugation and polarity with respect to circumconics.
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Given $\Delta ABC$ and angles $\alpha,\beta,\gamma\in(0,\pi)$ with $\alpha+\beta+\gamma=\pi$, we study the properties of the triangle $DEF$ which satisfies: (i) $D\in BC$, $E\in AC$, $F\in AB$, (ii) $\aangle D=\alpha$, $\aangle E=\beta$, $\aangle F=\gamma$, (iii) $\Delta DEF$ has the minimal area in the class of triangles satisfying (i) and (ii). In particular, we show that minimizer $\Delta DEF$, exists, is unique and is a pedal triangle, corresponding to a certain pedal point $P$. Permuting the roles played by the angles $\alpha,\beta,\gamma$ in (ii), yields a total of six such area-minimizing triangles, which are pedal relative to six pedal points, say, $P_1,....,P_6$. The main result of the paper is the fact that there exists a circle which contains all six points.
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References (3)
- Problem Section, Journal of Classical Geometry Volume 1, 2012
- Liang, Xuming. "New Results for Orthocenters." Dec 22, 2015. https://artofproblemsolving.com/community/c2671h1176952_new_results_for_orthocentersdue
- A. V. Akopyan and A. A. Zaslavsky. Geometry of conics, volume 26 of Mathematical World. American Mathematical Society, Providence, RI, 2007